(2x+5)(x^2+3x+1)=0

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Solution for (2x+5)(x^2+3x+1)=0 equation:


Simplifying
(2x + 5)(x2 + 3x + 1) = 0

Reorder the terms:
(5 + 2x)(x2 + 3x + 1) = 0

Reorder the terms:
(5 + 2x)(1 + 3x + x2) = 0

Multiply (5 + 2x) * (1 + 3x + x2)
(5(1 + 3x + x2) + 2x * (1 + 3x + x2)) = 0
((1 * 5 + 3x * 5 + x2 * 5) + 2x * (1 + 3x + x2)) = 0
((5 + 15x + 5x2) + 2x * (1 + 3x + x2)) = 0
(5 + 15x + 5x2 + (1 * 2x + 3x * 2x + x2 * 2x)) = 0
(5 + 15x + 5x2 + (2x + 6x2 + 2x3)) = 0

Reorder the terms:
(5 + 15x + 2x + 5x2 + 6x2 + 2x3) = 0

Combine like terms: 15x + 2x = 17x
(5 + 17x + 5x2 + 6x2 + 2x3) = 0

Combine like terms: 5x2 + 6x2 = 11x2
(5 + 17x + 11x2 + 2x3) = 0

Solving
5 + 17x + 11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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